Answer:Question 6: x = 5/2Question 7: b= 6Step-by-step explanation:Question 6:Given that:-2/5x + 3 = 2/3x + 1/3Taking variables (terms with x) on left and constants on right sideSigns of transferred terms will be changed-2/5x -2/3x = 1/3 - 3Taking LCM on both sides3/3*-2/5x - 2/3x*5/5 = 1/3 - 3*3/3-6x/15 -10x/15 = (1-9)/3-16x/15 = -8/3Multiplying both sides by -15/16-16x/15 * -15/16 = -8/3 * -15/16"-" sign when multiplied by "-" will give positive3 will be cancelled by 15 giving 58 will be cancelled by 16 giving 2x = 5/2Question 7: -2.6b + 4 = 0.9b - 17Taking variables (terms with x) on left and constants on right sideSigns of transferred terms will be changed-2.6b -0.9b = -17 -4-3.5b = -21Dividing both sides by -3.5b = -21/-3.5"-" sign will be cancelled outb = 6i hope it will help you!