Use deductive reasoning to show that the following procedure always produces the number 6. Procedure: Pick a number. Add 4 to the number and multiply the sum by 3. Subtract 6 and then decrease this difference by the triple of the original number.

Answer: procedure always produces 6Step-by-step explanation:Let 'n' be the unknown numberAdd 4 to the number : n+4multiply the sum by 3. multiply the sum n+4 by 3[tex]3(n+4) is 3n+12[/tex]Now subtract 6, so we subtract 6 from 3n+12[tex]3n+12-6=3n+6[/tex]finally decrease the difference by the tripe of the original numbertriple of original number is 3n[tex]3n+6-3n= 6[/tex]so the procedure always produces 6