There are 3 types of sweets in a jar. 3 Éclairs 2x+6 humbugs and x mints. A sweet is chosen at random. Work out the probability that it is a humbug.

Answer: P(choosing a humbug ) =[tex](\frac{2x+6}{3x+9} )[/tex]Step-by-step explanation:Total number of Eclairs = 3Total number of humbugs = 2x+ 6Total number of mints = xLet, E : Event of choosing a humbug out of the sweets jar[tex]\textrm{P(E)}  = \frac{\textrm{Total Number of favorable outcomes}}{\textrm{Total number of outcomes}}[/tex]or,[tex]\textrm{P( Event of choosing a humbug )} = \frac{\textrm{2x+6}}{\textrm{3 + (2x+6) + x}}[/tex]or, [tex]\textrm{P( Event of choosing a humbug )} = \frac{\textrm{2x+6}}{\textrm{3x+ 9}}[/tex]Hence, P(choosing a humbug ) =[tex](\frac{2x+6}{3x+9} )[/tex]